Centre of circle: (2, 1.25) Slope of line: 9/4 Equation of line: y-1.25 = 9/4(x-2) => 4y-5 = 9x-18 => 4y = 9x-13
no
9
9x+6 = 6x+15 9x-6x = 15-6 3x = 9 x = 3
no
9x + 3y = -54 3y = -9x - 54 y = -(3x + 18) Therefore, the y-intercept of this equation is y=-18.
9x+3y = 6 3y = -9x+6 y = -3x+2 which is now in slope-intercept form
If you mean y = -9x+11 then it is a straight line equation whereas -9 is the slope and 11 is the y intercept
-9x + y = 39 y = 9x + 39 The y-intercept is where x = 0 Therefore the y intercept is where: y - 9(0) = 39 y = 39 The y intercept is 39 The x-intercept is where y = 0 Therefore the y intercepet is where: 0 - 9x = 39 - 9x = 39 9x = - 39 x = -39/9
standard form equation is y = mx + b where m =slope and b = y intercept -9x + y = 21 add 9x to both sides y = 9x +21 b = y intercept = 21
Slope: -9
9x+18y = 36 18y = -9x+36 y = -1/2x+2 which is now in slope intercept form the slope being -1/2
Remember that slope-intercept form is: y = (slope)x + b 9x - 7y = 4 1) First, subtract 9x on both sides. -7y = -9x + 4 2) Then, divide both sides by -7. y = 9/7x + 4 3) There is your answer: y equals nine sevenths x plus 4.
-9/4 or -2.25
-7x+9y = 54 9y = 7x+54 y = 7/9x+6 which is now in slope-intercept form
Write the given equation in the slope-intercept form, y = mx + b, where m is the slope of the line.9x - 3y = -81 (subtract 9x to both sides)-3y = -9x - 81 (divide by -3 to both sides)y = 3x + 27Thus, the slope of the line is 3.
it equals 13X.