No. Your opponent would have a 10 point lead. Prime numbers are better to start with.
No.
No.
A multiple can be as large as you like. A factor can only be as large as the number which you start with.
If you start with 1, the common factors are 1 and 3. If you start with zero, as Fibonacci did, the common factor is 1.
To find the factor tree for 193, you start by determining the prime factors of 193. Since 193 is a prime number itself, the factor tree for 193 would simply consist of the number 193 at the top, as it cannot be broken down further into smaller prime factors. Therefore, the factor tree for 193 would just be a single branch with 193 as the prime factor.
12
56 28,2 14,2,2 7,2,2,2
There are many numbers with 12 prime factors. They are very, very big. The number with the lowest 12 prime factors is 7420738134810 if you start with 2 as the lowest factor. If you start with 1 as the lowest factor, then the number is 200560490130. 2048 has 12 factors.
You just have to divide the end product by the start out number
no because there are multiple ways to do factor trees until u get to all prime numbers
Start looking for factors; you already know that 1 is a factor, and that the number itself is a second factor (unless the number is 1). As soon as you find a factor that is neither 1 nor the number itself, the number is composite. If you find exactly two factors, the number is prime. If the number has only one factor, the number is 1, which is neither prime nor composite.
Start with putting ur number on top then list the multiples and what the are divided by to make that number.