The balanced chemical equation for the oxidation of sucrose (C12H22O11) can be written as: C12H22O11 + 12 O2 β 12 CO2 + 11 H2O.
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
You write it as an equation, and then solve the equation.
-12
15
4x12
n-12+4n++2_3n
7
2 x 2 x 3 = 12
Write an equation of 3/8Γ112
y/12 + 8 = 2
Ex: 3x-4y=12