Write the equation of the line that passes through the points
(3, -5) and (-4, -5)
y=-3x-2
the Equation of a Line Given That You Know Two Points it Passes Through.
Points: (2, 5) and (0, 5) Slope: 0 Equation: x = 2 meaning that it is a straight horizontal line parallel to the y axis
Since the slope of the line is 0, then the line is a horizontal line, and since the y-coordinates of the two points are 0, then the line lies on the x-axis. Thus, the equation of the line is y = 0.
Y=mx+b
Slope-intercept form
Points: (-3, -4) and (6, -1) Slope: 1/3 Equation: 3y = x-9
Points: (20, 18) and (35, 6) Slope: -4/5 Equation: y = -4/5x+34
y=-3x-2
the Equation of a Line Given That You Know Two Points it Passes Through.
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
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Points: (2, 5) and (0, 5) Slope: 0 Equation: x = 2 meaning that it is a straight horizontal line parallel to the y axis
Coordinate geometry
To find the equation of the line that passes through the points (-3, 0) and (0, 0), first determine the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Here, the slope is ( m = \frac{0 - 0}{0 - (-3)} = 0 ), indicating a horizontal line. Since both y-coordinates are 0, the equation of the line is ( y = 0 ).
To write a linear equation that passes through the origin, you can use the slope-intercept form, which is ( y = mx + b ), where ( m ) is the slope and ( b ) is the y-intercept. Since the line passes through the origin, the y-intercept ( b ) is 0, simplifying the equation to ( y = mx ). You can choose any value for the slope ( m ) to define the steepness of the line. For example, if you choose ( m = 2 ), the equation would be ( y = 2x ).
Y=2x+6