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X1 plus y2

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โˆ™ 2014-11-18 15:53:50

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When using the slope formula does it have to be (y2-y1)(x2-x1) or can it be (y1-y2)(x1-x2)?

If you mean: (y2-y1)/(x2-x1) and (y1-y2)/(x1-x2) then either works out the same.


How do you draw a square using line command?

Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);


X1 plus x2 divided by 2 y1 plus y2 divided by 2?

formula for the midpoint of a line


What is y2-y1x2-x1?

The equation (y2-y1)/(x2-x1) is known as the point-slope formula. It gives the slope for a line given two points of coordinatesÊ(x1, y1) and (x2, y2).


M is the midpoint of pq verify that this is the midpoint by using the distance formula to show tha pm equals mq?

Let P(x1, y1), Q(x2, y2), and M(x3, y3).If M is the midpoint of PQ, then,(x3, y3) = [(x1 + x2)/2, (y1 + y2)/2]We need to verify that,√[[(x1 + x2)/2 - x1]^2 + [(y1 + y2)/2 - y1]^2] = √[[x2 - (x1 + x2)/2]^2 + [y2 - (y1 + y2)/2]^2]]Let's work separately in both sides. Left side:√[[(x1 + x2)/2 - x1]^2 + [(y1 + y2)/2 - y1]^2]= √[[(x1/2 + x2/2)]^2 - (2)(x1)[(x1/2 + x2/2)) + x1^2] + [(y1/2 + y2/2)]^2 - (2)(y1)[(y1/2 + y2/2)] + y1^2]]= √[[(x1)^2]/4 + [(x1)(x2)]/2 + [(x2)^2]/4 - (x1)^2 - (x1)(x2) + (x1)^2 +[(y1)^2]/4 + [(y1)(y2)]/2 + [(y2)^2]/4 - (y1)^2 - (y1)(y2) + (y1)^2]]= √[[(x1)^2]/4 - [(x1)(x2)]/2 + [(x2)^2]/4 + [(y1)^2]/4 - [(y1)(y2)]/2 + [(y2)^2]/4]]Right side:√[[x2 - (x1 + x2)/2]^2 + [y2 - (y1 + y2)/2]^2]]= √[[(x2)^2 - (2)(x2)[(x1/2 + x2/2)] + [(x1/2 + x2/2)]^2 + [(y2)^2 - (2)(y2)[(y1/2 + y2/2)] + [(y1/2 + y2/2)]^2]]= √[[(x2)^2 - (x1)(x2) - (x2)^2 + [(x1)^2]/4 + [(x1)(x2)]/2 + [(x2)^2]/4 + (y2)^2 - (y1)[(y2) - (y2)^2 + [(y1)^2]/4) + [(y1)(y2)]/2 + [(y2)^2]/4]]= √[[(x1)^2]/4 - [(x1)(x2)]/2 + [(x2)^2]/4 + [(y1)^2]/4 - [(y1)(y2)]/2 + [(y2)^2]/4]]Since the left and right sides are equals, the identity is true. Thus, the length of PM equals the length of MQ. As the result, M is the midpoint of PQ


How do you find the slopes of a line?

Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2


How do you find linear equations with just coordinates?

if we take the (x1,y1),(x2,y2) as coordinates the formula was (x-x1)/(x2-x1)=(y-y1)/(y2-y1)


How do you do equations and graphs for slope?

The equation for the slope between the points A = (x1, y1) and B = (x2, y2) = (y2 - y1)/(x2 - x1), provided x1 is different from x2. If x1 and x2 are the same then the slope is not defined.


How do you get the distance?

The distance between two points, (x1,y1) , (x2,y2) = squareroot[(x2-x1)2 + (y2-y1)2]


How do you find the equation of a line when given 2 coordinates?

(y -y1)=(x -x1)(y2 -y1)/(x2 -x1) defines the line containing coordinates (x1,y1) and (x2.y2).


What is the mathematical equation of slope?

The slope between two points, (x1, y1) and (x2, y2) is: (y1 - y2) / (x1 - x2)


How do you solve for slope from two points and a graph?

Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2


What is the equation to find the midpoint?

The mid-point of the line segment of (x1, y1) and (x2, y2) is (x1+X2)/2 and (y1+y2)/2


Can you evaluate 4xy for x1 y2?

It is 8.


What is the formula to calculate the slope?

It's m = y2 - y1/ x2- x1 It's m equals y2 minus y1 over x2 minus x1


How do you determine the slope of a line on an graph?

Rise divided by run. (Y2 - Y1) / (X2 - X1) - with (X1, Y1) and (X2, Y2) being two points on the graph.


What is the slope formula in equation form?

If (x1, y1) and (x2, y2) are two points on the line, then the formula for the slope is (y2-y1)/(x2-x1) provided x2 ≠ x1. If x2 = x1 then the line is vertical and the slope is not defined.


How do you determine slope?

(y2-y1)/(x2-x1)


What formula is used to find the length between two points in a coordinate plane?

It is the Pythagorean distance formmula.If P = (x1, y1) and Q = (x2, y2) thenDistance between P and Q = sqrt[(x1 - x2)2 + (y1 - y2)2]It is the Pythagorean distance formmula.If P = (x1, y1) and Q = (x2, y2) thenDistance between P and Q = sqrt[(x1 - x2)2 + (y1 - y2)2]It is the Pythagorean distance formmula.If P = (x1, y1) and Q = (x2, y2) thenDistance between P and Q = sqrt[(x1 - x2)2 + (y1 - y2)2]It is the Pythagorean distance formmula.If P = (x1, y1) and Q = (x2, y2) thenDistance between P and Q = sqrt[(x1 - x2)2 + (y1 - y2)2]


How do you draw a line on Java Graphics?

Drawing a line from (x1, y1) to (x2, y2) using a default Graphics object: graphics.drawLine(x1, y1, x2, y2);


What is y2 plus y2?

y2 + y2 = 2y2


What does m equal in y equals mx plus b?

m = the slope of the line. rise/run. Y2 - Y1/X2 - X1


How can you find the length of a line segment in the coordinate plane?

The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2


How do you figure slope?

Slope= y2-y1 /x2-x1


How do you find the slope of line?

(y2-y1)/(x2-x1)

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