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Oh honey, you've got yourself a classic case of finding the average of two points in a coordinate plane. All you need to do is add the x-coordinates (x1 + x2) and divide by 2 to get the x-coordinate of the midpoint. Then do the same for the y-coordinates (y1 + y2), divide by 2, and voila, you've got the y-coordinate of the midpoint. Easy peasy lemon squeezy!
What else can I help you with?
How do you find a midpoint between two points on a graph?
Given two coordinates (x1,y1) and (x2,y2) The midpoint is ( ((x2+x1)/2) , ((y2+y1)/2) )
When using the slope formula does it have to be (y2-y1)(x2-x1) or can it be (y1-y2)(x1-x2)?
Oh, don't you worry, friend! When using the slope formula, whether you do (y2-y1)/(x2-x1) or (y1-y2)/(x1-x2), the answer will be the same! It's all about the difference in vertical and horizontal values, and as long as you stay consistent in your calculations, you'll find the slope just fine. Just trust your instincts and enjoy the process of solving the equation.
Formula to find the midpoint in co-ordinate geometry?
midpoint=(X1 + X2, Y1 + Y2)divide both of those by 2.X1 + X2 divided by 2 should give you the co ordinate for X.
How can you find the length of a line segment in the coordinate plane?
The formula is the square root of: (x2-x1)^2 plus (y2-y1)^2
How do you find projective line if I have to points x1 y1 and x2 y2?
False. -apex
How do you draw a square using line command?
Line (x1, y1, x2, y1); Line (x2, y1, x2, y2); Line (x2, y2, x1, y2); Line (x1, y2, x1, y1);
How do you determine the slope of a line on an graph?
Rise divided by run. (Y2 - Y1) / (X2 - X1) - with (X1, Y1) and (X2, Y2) being two points on the graph.
What is the equation to find slope?
m = y2 - y1 divided by x2 - x1
What is the formula for midpoint?
( x1 + x2) divided by 2 then (y1 +y 2) divided by 2
M is the midpoint of pq verify that this is the midpoint by using the distance formula to show tha pm equals mq?
Let P(x1, y1), Q(x2, y2), and M(x3, y3).If M is the midpoint of PQ, then,(x3, y3) = [(x1 + x2)/2, (y1 + y2)/2]We need to verify that,√[[(x1 + x2)/2 - x1]^2 + [(y1 + y2)/2 - y1]^2] = √[[x2 - (x1 + x2)/2]^2 + [y2 - (y1 + y2)/2]^2]]Let's work separately in both sides. Left side:√[[(x1 + x2)/2 - x1]^2 + [(y1 + y2)/2 - y1]^2]= √[[(x1/2 + x2/2)]^2 - (2)(x1)[(x1/2 + x2/2)) + x1^2] + [(y1/2 + y2/2)]^2 - (2)(y1)[(y1/2 + y2/2)] + y1^2]]= √[[(x1)^2]/4 + [(x1)(x2)]/2 + [(x2)^2]/4 - (x1)^2 - (x1)(x2) + (x1)^2 +[(y1)^2]/4 + [(y1)(y2)]/2 + [(y2)^2]/4 - (y1)^2 - (y1)(y2) + (y1)^2]]= √[[(x1)^2]/4 - [(x1)(x2)]/2 + [(x2)^2]/4 + [(y1)^2]/4 - [(y1)(y2)]/2 + [(y2)^2]/4]]Right side:√[[x2 - (x1 + x2)/2]^2 + [y2 - (y1 + y2)/2]^2]]= √[[(x2)^2 - (2)(x2)[(x1/2 + x2/2)] + [(x1/2 + x2/2)]^2 + [(y2)^2 - (2)(y2)[(y1/2 + y2/2)] + [(y1/2 + y2/2)]^2]]= √[[(x2)^2 - (x1)(x2) - (x2)^2 + [(x1)^2]/4 + [(x1)(x2)]/2 + [(x2)^2]/4 + (y2)^2 - (y1)[(y2) - (y2)^2 + [(y1)^2]/4) + [(y1)(y2)]/2 + [(y2)^2]/4]]= √[[(x1)^2]/4 - [(x1)(x2)]/2 + [(x2)^2]/4 + [(y1)^2]/4 - [(y1)(y2)]/2 + [(y2)^2]/4]]Since the left and right sides are equals, the identity is true. Thus, the length of PM equals the length of MQ. As the result, M is the midpoint of PQ
What is the formula for calculating gradient?
change in Y divided by change in X. X is your field value(kilometers, miles, feet, etc) and Y is the units of your isolines(degrees, feet, meters, etc) Y2-Y1 / X2-X1 = Y2-Y1 DIVIDED BY X2-X1
How do you find linear equations with just coordinates?
if we take the (x1,y1),(x2,y2) as coordinates the formula was (x-x1)/(x2-x1)=(y-y1)/(y2-y1)
What is the formula to calculate the slope?
It's m = y2 - y1/ x2- x1 It's m equals y2 minus y1 over x2 minus x1
How do you do equations and graphs for slope?
The equation for the slope between the points A = (x1, y1) and B = (x2, y2) = (y2 - y1)/(x2 - x1), provided x1 is different from x2. If x1 and x2 are the same then the slope is not defined.
How do you find the equation of a line when given 2 coordinates?
(y -y1)=(x -x1)(y2 -y1)/(x2 -x1) defines the line containing coordinates (x1,y1) and (x2.y2).
How do you solve for slope from two points and a graph?
Points: (x1, y1) and (x2, y2) Slope: y1-y2/x1-x2
What is the mathematical equation of slope?
The slope between two points, (x1, y1) and (x2, y2) is: (y1 - y2) / (x1 - x2)
