0
x2 + 10 x + 25 = 2
(x+5)2 = 2
x+5 = +/- sqrt(2)
x = -5 +/- sqrt(2)
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What is X2 plus 10x plus 21 equals?
x2 + 10x + 21 = (x + 3)(x + 7)
What is the radius of x2 plus y2 - 10x plus 4y - 52 equals 0?
Complete the squares: x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29 x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81 So the radius is sqrt(81) = 9
What is the area of a square with a side whose length equals x plus 5?
x2+10x+25
How do you solve x2-10x plus 25 equals 64?
x2 - 10x + 25 = 64 Or x2 - 10x + 25 = 64? If the first, move all over to 1 side; x2 - 10x + 25 - 64 = 0 x2 - 10x + -39 = 0 Then make it into quadratic equations; (x - 13)(x + 3) = 0 Therefore x = 13 or x = -3. If the second, 8x = -39 -39/8 = -9.75 = x
Which equation represents y equals x2-10x plus 30 in vertex form?
y=x2-10x+30=(x-5)2-25+30=(x-5)2+5
How do you answer the problem x2 plus 10x plus equals 0?
x2 + 10x = 0 x2 + 10x + 25 = 25 (x + 5)2 = 25 x + 5 = +-5 x1 = 0 x2 =10
X2-10x plus 25 equals 0?
x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5
What number must you add to complete the square x2 plus 10x equals 8?
Twenty-Five x2 + 10x = 8 x2 + 10x + 25 = 8 + 25 (x + 5)2 = 33
What is X2 plus 10x plus 21 equals?
x2 + 10x + 21 = (x + 3)(x + 7)
What is the radius of x2 plus y2 - 10x plus 4y - 52 equals 0?
Complete the squares: x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29 x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81 So the radius is sqrt(81) = 9
What is the area of a square with a side whose length equals x plus 5?
x2+10x+25
What is the line of symmetry for the parabola whose equation is y equals x2 plus 10x plus 25?
When x = -5
How do you find the radius of the circle with the given equation of x2 plus y2-10x plus 4y plus 4 equals 0?
Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.
How do you solve x2-10x plus 25 equals 64?
x2 - 10x + 25 = 64 Or x2 - 10x + 25 = 64? If the first, move all over to 1 side; x2 - 10x + 25 - 64 = 0 x2 - 10x + -39 = 0 Then make it into quadratic equations; (x - 13)(x + 3) = 0 Therefore x = 13 or x = -3. If the second, 8x = -39 -39/8 = -9.75 = x
X2 - 10x plus 25?
depends on what x is
Which equation represents y equals x2-10x plus 30 in vertex form?
y=x2-10x+30=(x-5)2-25+30=(x-5)2+5
What is the answer to x2 plus 9 equals 10x?
x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.
