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Q: How do you answer the problem x2 plus 10x plus equals 0?

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x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.

x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5

When x = -5

X2 + 8x + 16 = 10x +16x2 + 8x + 16=2x + 8x + 16=10x + 16

Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.

Related questions

x2 + 10x + 21 = (x + 3)(x + 7)

For a start you tell us what the expression equals....

x2 + 9 = 10x x2 - 10x + 9 = 0. (x - 9)(x - 1) = 0. Therefore, x = 1 or 9.

x = -3.27 or -6.73

-6

-2-5

Twenty-Five x2 + 10x = 8 x2 + 10x + 25 = 8 + 25 (x + 5)2 = 33

x2 - 10x + 25 = 0(x - 5)(x - 5) = 0x - 5 = 0x = 5

x2+10x+1 = -12+2x x2+10x-2x+1+12 = 0 x2+8x+13 = 0 Solving by using the quadratic equation formula: x = - 4 - or + the square root of 3

(x + 8)(x + 2)

(5,-5)

x2+10x-336

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