Complete the squares:
x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29
x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81
So the radius is sqrt(81) = 9
If: 4y+10x = 16Then: 4y = -10x+16And: y = -2.5x+4
10x + 2y + 8z - 5x + 4z - 4y = 10x - 5x + 2y - 4y + 8z + 4z = (10 - 5)x + (2 - 4)y + (8 + 4)z = 5x - 2y + 12z
6x - 4y
10x - 3y + 2x - 4y =(10x + 2x) + (-3y - 4y) =12x - 7y
10x+4y+11xy
If: 4y+10x = 16Then: 4y = -10x+16And: y = -2.5x+4
Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.
6x - 4y
10x + 2y + 8z - 5x + 4z - 4y = 10x - 5x + 2y - 4y + 8z + 4z = (10 - 5)x + (2 - 4)y + (8 + 4)z = 5x - 2y + 12z
x2 + y2 - 10x + 4y - 52 = 0 x2 - 10x + y2 + 4y = 52 Complete the square (x2 - 10x + 25) + (y2 + 4y + 4) = 52 + 25 + 4 (x - 5)2 + (y + 2)2 = 81 (x - 5)2 + (y - -2)2 = 92 This is the equation of a circle with center (5, -2), and radius 9.
10x - 3y + 2x - 4y =(10x + 2x) + (-3y - 4y) =12x - 7y
Two straight lines that intersect.
10x+4y+11xy
10x+2x-3y-4y=12x-7y
That depends on the numerical values of 'x' and 'y'. When either of them changes, the value of (10x + 4y) changes.
8x plus 4y equals 5 is 8x + 4y = 5.
How do you solve 4y plus x equals 8