Best Answer

x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0

(x + 9)(x + 5) = 0 so that x = -5 or x = -9

Q: X2 plus 14x plus 45 equals 0?

Write your answer...

Submit

Still have questions?

Continue Learning about Math & Arithmetic

x2 - 14x + 45 = (x - 9)(x - 5)

16x = -5 x = -.3125

x2 + 14x + 48 = (x + 8)(x + 6)

49-apex

x2 - 14x = -49 ∴ x2 - 14x + 49 = 0 ∴ (x - 7)2 = 0 ∴ x = 7

Related questions

x2 - 14x + 45 = (x - 9)(x - 5)

x2 - 14x + 45 = (x - 5)(x - 9).

-x2+14x=49

The roots are: x = -5 and x = -9

x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5

-x2-14x-45 = -(x2+14x+45) delta = 142-4*1*45=16 so x2+14x+45=(x-(-14+4)/2) (x-(-14-4)/2) = (x+5)(x+9) so -x2-14x-45 = -(x+5)(x+9)

16x = -5 x = -.3125

(x2 + 14x + 49) = (x + 7)2

x2 + 14x + 48 = (x + 8)(x + 6)

49 x2 + 14x = -7 x2 + 14x + 49 = 42 (x + 7)2 = 42 x = -7 ± √42

49-apex

The given expression does not have rational factors, so the question cannot be abut factorising. Evaluating x2 - 14x + 9 depends on the value of x.