Q: Factor x2 - 14x plus 45?

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-3+-11 = -14 and -3*-11 = 33 So: x2-14x+33 = (x-3)(x-11) when factored

x2-14x+45=0(x-9)(x-5)=0x-9=0 & x-5=0x=9 & x=5

x2+14x+40 = (x+4)(x+10) when factored

x2-14x+24=(x-12)(x-2) Since there are no options listed in this question ;), the answer could be either "x-12" or "x-2". How to factor a trinomial: see link.

49 x2 + 14x = -7 x2 + 14x + 49 = 42 (x + 7)2 = 42 x = -7 ± √42

Related questions

x2 - 14x + 45 = (x - 9)(x - 5)

x2 - 14x + 49(x - 7) (x - 7)

x2+14x+40 = (x+4)(x+10) when factored

x2 + 14x + 45 = (x + 9) (x + 5)

-x2-14x-45 = -(x2+14x+45) delta = 142-4*1*45=16 so x2+14x+45=(x-(-14+4)/2) (x-(-14-4)/2) = (x+5)(x+9) so -x2-14x-45 = -(x+5)(x+9)

x2 + 14x + 45 = 0 => x2 + 9x + 5x + 45 = 0 => x(x + 9) + 5(x + 9) = 0 (x + 9)(x + 5) = 0 so that x = -5 or x = -9

(x2 + 14x + 49) = (x + 7)2

(x - 3)(x - 11)

-3+-11 = -14 and -3*-11 = 33 So: x2-14x+33 = (x-3)(x-11) when factored

x2 + 14x + 48 = (x + 8)(x + 6)

(x + 10)(x + 4)

-x2+14x=49