0
I think this is how you do it:
x2+2x = 8
x2+2x+(1/2*(2))2 = 8 + (1/2*(2))2
x2+2x+1=8+1
(x+1)2 = 9
SQ.ROOT [(x+1)2 = 9]
x+1 = 3 and x+1 = -3
so,
x=2 and x=-4
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∙ 13y ago
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