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Q: X2 plus y2 equals 4

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(2-r)e-rr

x2 +y2 = R2 =16 = radius 2 R = 4

I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.

x2 + y2 - 5y + 4 = 0 x2 + y2 - 5y = - 4 x2 + y2 - 5y + 25/4 = - 4 + 25/4 = 9/4 x2 + (y - 5/2)2 = (3/2)2 Centre = (0, 5/2) and radius = 3/2

The one which says: y2 = 4 - 4/25 x2

Complete the squares: x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29 x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81 So the radius is sqrt(81) = 9

Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.

x2 -y2 +4y-4=(x+y)(x-y)+4y-4

y2=-x2-8x+6

If that equals 16 then the radius is 4

If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2

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