The graph of that equation is a circle, centered at the origin, with radius = 2 .
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I think you have missed out an equals sign. If you mean x2 + y2 = 16, then the radius is 4.
x2 + y2 - 5y + 4 = 0 x2 + y2 - 5y = - 4 x2 + y2 - 5y + 25/4 = - 4 + 25/4 = 9/4 x2 + (y - 5/2)2 = (3/2)2 Centre = (0, 5/2) and radius = 3/2
Complete the squares: x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29 x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81 So the radius is sqrt(81) = 9
If:xy = x2 + y2 + 2xyThen:x2 + xy + y2 = 0Do you want to solve it for x?x2 + xy + (y/2)2 = (y/2)2 - y2(x + y/2)2 = y2/4 - y2x + y/2 = ± √(-3y2/4)x = -y/2 ± y√(-3) / 2x = (-y ± yi√3) / 2