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X 2-y 2 1 is not an equation nor even an expression.

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Q: X 2-y 2 1 is a hyperbola Parallelogram Square Rectangle Not?
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The length of a rectangle is twice its width The perimeter is 60 feet Find its area?

Let x be the length and y be the width.x=2yPerimeter = 2 x length + 2 x width = 2x+2y = 2(2y)+2y = 4y+2y=6y6y = 60y=10width is 10Length is 2y = 20Area = length x width = 20 x 10 = 200 square feet


If the length of a rectangle is 4yards longer than the width and the perimeter is 40 yards what is the area?

let x=length of rectangle let y=width of rectangle x=y+5 2x+2y=40 2(y+5)+2y=40 2y+10+2y=40 4y+10=40 4y=30 4y=7.5 x=7.5+5 x=12.5 AREA: 12.5 x 7.5 = 93.75 YARDS


What is the length of a rectangle that has area of 392 sq cm and a length twice the width?

A rectangle has 4 sides. Let the width of the rectangle be y. As the length of the rectangle is twice its width, it is 2y. The sum of the 2 sides that are the width: 2 * y = 2y The sum of the 2 sides that are the length: 2y * 2 = 4y The perimeter equals the 2 widths and the 2 breadths: 2y + 4y = 6y The perimeter: 6y = 60 cm So: y = 10 cm The length is 2y = 2 * 10 cm = 20 cm Answer: 20 cm


The area of a rectangle is given by A equals 6x2y plus 4y2x and the width of the rectangle is w equals 2xy What is the length L of the rectangle if L equals A w?

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How do you solve - A rectangle has a width of 2y plus 3 and height of y-7. Find the perimeter of the rectangle?

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If you double the side lengths of a rectangle why is the area of the new rectangle not twice as big as the original?

Look at it this way, suppose x is one side of the rectangle and y is the other. Then the area of the rectangle would be xy. Now if you double each side of the originial rectangle you would have each side as 2x and 2y. So the area of the new rectangle would be 2x*2y or 4xy. As you can see the new area is 4 times larger than the original.


A rectangle has a width of 2y plus 3 and height of y-7. Find the perimeter of the rectangle?

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If a square is divided into five congruent rectangles and the perimeter of one of the rectangles is 30centimeters what is the area of the square?

x y y y y y Perimeter of each rectangle = 2x + 2y = 30 which can be reduced: x + y = 15 Thus the perimeter of square = 2x + 10y Since it is a square: x = 5y Replacing values in equation: 2(5y) + 2y = 30 Solving for y: 10y + 2y = 30 : 12y = 30 : y = 2.5 Which means x = 12.5 Area of square = (12.5)2 = 156.25 cm2 Checking that numbers fit original: 2(12.5) + 2(2.5) = 25 + 5 = 30


Completing the square in algebra?

X+y^2+2y=-1


The square of the product of x and y?

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Perimeter is the sum of all of the sides, so perimeter can be written as P=2x + 2y First you need to plug in the values you know 360 = 2(84) + 2y Multiply 360=168 + 2y Subtract 192=2y and divide y=96 feet so the length is 96 feet


What is the perimeter of the rectangle in which A equals 2xymi?

The question doesn't nail it down; i.e., there can be several answers that satisfy the given information. Perimeter 'P' = 2 x (Length + Width) Area 'A' = (Length) x (Width) = 2 x y What is the Length, and what is the Width ? Here are five correct answers: ==> If the rectangle is (2) by (x y), A = 2xy, P = 4 + 2xy ==> If the rectangle is (2x) by (y), A = 2xy, P = 4x + 2y ==> If the rectangle is (x) by (2y), A = 2xy, P = 2x + 4y ==> If the rectangle is (1) by (2xy), A = 2xy, P = 2 + 4xy ==> If the rectangle is (0.1) by (20xy), A = 2xy, P = 0.2 + 40xy