To find the perimeter of a polygon, just add the length of all the sides. In this case, the four sides of the rectangle.
The perimeter of a rectangle = 2 (w + h) where w is the width and h is the height.Accordingly, perimeter = 2 ( 2y + 3 + y - 7) = 2 (3y - 4) = 6y - 8
You divide the perimeter by the width and you get the lenght
you need length and width length multiply width = area length + length + width + width = perimeter
all you have to do is add together the four sides. 2L+2W=Perimeter (L=length or base, W=Width or height)
Add together the lengths of each of its sides.
Length + length + width + width = perimeter. Length + width x 2 = perimeter
The length of a rectangle is twice its width. If the perimeter of the rectangle is , find its area.
the length of a rectangle is 5 more then the width. Find the perimeter and the area of the rectangle
If the length of a rectangle is twice its width and it has a perimeter of 48, then the rectangle is 16 in length and 8 in width.
You divide the perimeter by the width and you get the lenght
you need length and width length multiply width = area length + length + width + width = perimeter
all you have to do is add together the four sides. 2L+2W=Perimeter (L=length or base, W=Width or height)
Add together the lengths of each of its sides.
Length + length + width + width = perimeter. Length + width x 2 = perimeter
perimeter = 2 x (length + width) ⇒ length + width = perimeter ÷ 2 ⇒ length = (perimeter ÷ 2) - width So to find the length of the given rectangle, subtract the width from half the perimeter is how to do it. IF you meant "What is the length..." then: length = perimeter ÷ 2 - width = 40 ÷ 2 - 2 in = 20 - 2 in = 18 in
Height = (Perimeter/2) - Base
Perimeter = 2 * width + 2 * length, so rearranging --> width = (Perimeter / 2) - length
Length = (Perimeter - twice width) / 2