It is: 3x2+6x-11 = 0

3x(2x + 1)

(2x-4)(x-1) = 0

From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5

7x + 2 = 6x + 2 if and only x = 0.

y=6x² is already solved. the parabola will touch the x-axis at x=0.

2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34

6x+5=3x+5 5=9x+5 x=0

x^2 + 3x + 7 = 6x + 18 x^2 - 3x - 11 = 0

If: x+3+6x+9 = 0 then 7x+12 = 0 So: 7x = -12 and x = -12/7

2x2 - 6x + 4 = 0 2(x2 - 3x + 2) = 0 2(x - 1)(x - 2) = 0 x - 1 = 0 and x - 2 = 0 So, x = 1 and x = 2.

2x2+6x-8 = 72 2x2+6x-8-72 = 0 2x2+6x-80 = 0 (2x-10)(x+8) = 0

x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)

63828

If: 6x^2 +2x +k = 0 has equal roots Then using the discriminant of b^2 -4ab=0: 4 -24k=0 => k=-4/-24 => k=1/6 Therefore the value of k = 1/6

2x2 + 6x - 8 = 72 ∴ 2x2 + 6x + 64 =0 ∴ x2 + 3x + 32 = 0 This can not be factored, as x is not equal to any integer. Using the quadratic equation, we find that: x = -3/2 ± √119 / 2i

6x+2y-3 = 0 2y = -6x+3 y = -3x+3/2 in slope intercept form

x(x + 2)(x + 3) x = 0, -2, -3

x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3

A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}

the answer is -3x = 0

x2 + 6x = 0 The only factor common to both terms is 'x'. x(x + 6) = 0 To solve this equation then one or both of the factors must equal zero. Then x = 0, or x + 6 = 0 which occurs when x = -6.

x2+6x-40 = 0 (x+10)(x-4) = 0 x = 4 or x = -10

-6x + 0 = 45 Simplifies to: -6x = 45. By dividing both sides by -6, we arrive at the final: x = -45/6

8x + 16 = 6x -> 2x + 16 = 0 -> 2x = -16 -> x = -8

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