Q: X squared plus 6x plus 8 equals 0?

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7x + 2 = 6x + 2 if and only x = 0.

x2 + 6x + 9 = 81 x2 + 6x = 72 x2 + 6x - 72 = 0 (x+12)(x-6) = 0 x= -12, 6 (two solutions)

A quadratic equation. If you wish to solve for x, you can do so as follows: -x2 + 6x + 7 = 0 x2 - 6x - 7 = 0 (x - 7)(x + 1) = 0 x ∈ {-1, 7}

x2 + 6x + 12 = 0 x2 + 6x + 9 = -3 (x + 3)2 = -3 x + 3 = ± √-3 x = -3 ± i√3

5x2 - 6x = 0Factor the left side:x (5x - 6) = 0The equation is satisfied ifx = 0,or if5x - 6 = 05x = 6x = 6/5

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It is: 3x2+6x-11 = 0

3x(2x + 1)

(2x-4)(x-1) = 0

From what i understand the equation is like this; (3 * 2 ) + 6x + 24 = 0 6 + 6x +24 = 0 6x = - 24 - 6 6x = - 30 x = - 5

2x2 - 6x - 25 = 0. Solutions are 5.34 and -2.34

y=6x² is already solved. the parabola will touch the x-axis at x=0.

7x + 2 = 6x + 2 if and only x = 0.

2x2 - 6x + 4 = 0 2(x2 - 3x + 2) = 0 2(x - 1)(x - 2) = 0 x - 1 = 0 and x - 2 = 0 So, x = 1 and x = 2.

x+15+(-15)=6x+(15+(-15)=6x+(15-15)=6x+(0)=6x+0=6Add/subtract 0 from both sides,x=6

2x2 + 6x - 8 = 72 ∴ 2x2 + 6x + 64 =0 ∴ x2 + 3x + 32 = 0 This can not be factored, as x is not equal to any integer. Using the quadratic equation, we find that: x = -3/2 ± √119 / 2i

6x+5=3x+5 5=9x+5 x=0

x^2 + 3x + 7 = 6x + 18 x^2 - 3x - 11 = 0