x2 + 6x + 12 = 0
x2 + 6x + 9 = -3
(x + 3)2 = -3
x + 3 = ± √-3
x = -3 ± i√3
(9,6)
one
In 6x + 4 = 12, x = 4/3
6x+4 = x+12+4x-6 6x-x-4x = 12-6-4 x = 2
It has roots x = 2.618 and x = 0.38197
6x+4=3x+12 => 6x-3x=12-4 => 3x=8 => x=8/3=2.666...
x would be -3
x^2+6x+2=9 x^2+6x-7=0 (x+7)(x-1)=0 x=-6,1 for your roots
No answer in integers. Quadratic formula gives roots as -1.268 and -4.732
3x+42=6x+12 42=6x-3x+12 42=3x+12 42-12=3x 30=3x 10=x
4x + 6 = 6x - 12-4x -4x6 = 2x - 12+12 +1218 = 2xx=9
In this equation, x=6.