set up a system of equations x+y=45 xy=200 set one equal to a variable x=-y+45 plug it into the other equation y(-y+45)=200 distribute the y -y2+45y=200 set it equal to 0 -y2+45y-200=0 take out the negative -(y2-45y+200)=0 factors of 200 are 1&200, 2&100, 4&50, 5&40, 10&20 5 and 40 = 45 factor -(y-5)(y-40)=0 solve for y y=5,40 this is the proper way to do this or you could just guess and check hope i helped :)
265
a constant
18010% off of $200= 10% discount applied to $200= $200 - (10% * $200)= $200 - (0.10 * $200)= $200 - 20= 180
No, 50 is double of 25 so....if X = 50 Y = 25 X - Y = 25 25 / Y = 1 1 * 100 = 100% 100% is double. -------------------------------------------------------------------------------------------------------------------------------------------------- X = 50 Y = 25 X/Y = 2 X = 2 x Y <------- statement 1 X/Y = 2 X/Y = 2 x 100% = 200% X = 200% of Y <------ statement 2 By statement 1 & 2, 200% is equivalent to double.
If: 30y = 10+y Then: y = 10/29
20
y
32.134 = (3 x 10) + (2 x 1) + (1/10) + (3/100) + (4/1000)
The Y intercept of y=7x+10 is 10.
It is: 200*10 = 2000
To find 10 more than a given number y, you simply add 10 to y. This can be represented as y + 10. For example, if y = 5, then 10 more than y would be 5 + 10 = 15. So, the expression "10 more than y" can be simplified to y + 10.