190
set up a system of equations x+y=45 xy=200 set one equal to a variable x=-y+45 plug it into the other equation y(-y+45)=200 distribute the y -y2+45y=200 set it equal to 0 -y2+45y-200=0 take out the negative -(y2-45y+200)=0 factors of 200 are 1&200, 2&100, 4&50, 5&40, 10&20 5 and 40 = 45 factor -(y-5)(y-40)=0 solve for y y=5,40 this is the proper way to do this or you could just guess and check hope i helped :)
265
a constant
18010% off of $200= 10% discount applied to $200= $200 - (10% * $200)= $200 - (0.10 * $200)= $200 - 20= 180
Let's denote the two numbers as x and y. We know that x + y = 30 and xy = 200. To solve this system of equations, we can substitute y = 30 - x into the second equation. This gives us x(30 - x) = 200. Simplifying, we get x^2 - 30x + 200 = 0. By solving this quadratic equation, we find that the two numbers are 20 and 10.
20
If: 30y = 10+y Then: y = 10/29
It is: 200*10 = 2000
y
32.134 = (3 x 10) + (2 x 1) + (1/10) + (3/100) + (4/1000)
The Y intercept of y=7x+10 is 10.
10 x 20 = 200