y
What is the product of y and 10
To find two numbers where the difference is 7 and the product is 30, we can set up the equations: ( x - y = 7 ) (difference) and ( x \cdot y = 30 ) (product). Solving these equations, we can express ( x ) as ( y + 7 ) and substitute it into the product equation to find the values of ( x ) and ( y ). The numbers that satisfy both conditions are 10 and 3, since ( 10 - 3 = 7 ) and ( 10 \cdot 3 = 30 ).
x = 10, y = 25
1/x + 1/y y/xy + x/xy (y+x)/xy= 10/20 10/20=1/2 1/2 is the answer.
The two numbers that have a difference of 6 and a product of 40 are 10 and 4. To find them, you can set up the equations: ( x - y = 6 ) and ( xy = 40 ). Solving these gives you ( x = 10 ) and ( y = 4 ) (or vice versa).
Suppose the numbers are x and y Then the sum of their reciprocals is 1/x + 1/y = y/xy + x/xy = (y+x)/xy = 10/20 = 1/2
Put 0 in for x and solve for y to find the y intercept. Put 0 in for y and solve for x to find the x intercept. -4(0)+3y=10 y=10/3 y intercept is (0,10/3) -4x+3(0)=10 x=-10/4 x intercept is (-10/4,0)
8
To find two numbers where the difference is 9 and the product is 22, let’s denote the numbers as ( x ) and ( y ). We have the equations: ( x - y = 9 ) and ( x \cdot y = 22 ). Solving these, we can express ( x ) as ( y + 9 ) and substitute this into the product equation, leading to ( (y + 9) \cdot y = 22 ). This results in the quadratic equation ( y^2 + 9y - 22 = 0 ), which can be solved to find the values of ( x ) and ( y ).
y = 7x-10
2x+y = 10 or y = -2x + 10 so the slope is -2
2y+5y=10 7y=10 y=10/7