yes that is correct
y2 + 10z - 10y - yz = y2 - 10y - yz + 10z = y(y - 10) - z(y - 10) = (y - 10)(y - z)
(y - 8)(y - 2)
9
5. A circle with centre (0,0) has equation: x2 + y2 = radius2 With: x2 + y2 = 25 = 52 The radius is 5.
The one which says: y2 = 4 - 4/25 x2
A circle, centre (0,0), radius = 5
Complete the squares: x2 - 10x + 25 + y2 + 4y + 4 - 52 = 25 + 4 = 29 x2 - 10x + 25 + y2 + 4y + 4 = 52 + 29 = 81 So the radius is sqrt(81) = 9
X2+y2=25 (x-8)2+y2 =41
No, not if the y is squared. When graphed the equation will not form a straight line.
Given: x2 + y2 - 10x + 4y + 4 = 0 First, we'll move our constants to the right: x2 + y2 - 10x + 4y = -4 Then group terms with the same variables together: x2 - 10x + y2 + 4y = -4 Then complete the squares: x2 - 10x + 25 + y2 + 4y + 4 = -4 + 25 + 4 (x - 5)2 + (y + 2)2 = 25 And there we have it. This is an equation for a circle whose center point is at (5, -2), with a radius of √25, which equals 5.
Without an equality sign the given terms can't be considered to be the equation of a circle.
(2-r)e-rr