yx-3 is not an equation, and it has no graph.
0
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
y=x^3
The inverse of 3 is 1/3.
The reciprocal (multiplicative inverse) of -3 is -1/3.The reciprocal (multiplicative inverse) of -3 is -1/3.The reciprocal (multiplicative inverse) of -3 is -1/3.The reciprocal (multiplicative inverse) of -3 is -1/3.
I don’t know
Multiplicate inverse of -3 is - 1/3.
3 for A+
the inverse of x+3
So y = (3x - 4)/2. To find the find the inverse equation, y-1,(1) Rewrite the equation replacing all ys with xs and all xs with ys.x = (3y - 4)/2(2) Solve the new equation for yx = (3y - 4)/22x = 3y - 42x + 4 = 3y(2x + 4)/3 = yThis is your inverse equation!y-1 = (2x + 4)/3
How would you prove algebraically that the following function is one to one? f(x)= (x+3)^2 , x>= -3?