The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
First you express the numbers as their prime factors: 3y = 3, y y2 = y, y Next you identify any common prime factors. In this case both numbers have y as a prime factor. Finally you multiply the numbers and divide by the HCF: 3y(y2)/y = 3y2 and thus the LCM is 3y2
(x + 5y)(x - 3y)
-3(x + y + z)
(x)(x+y) ....or..... x2+xy
(y^2 + 3)(y^2 - 3y + 3)(y^2 + 3y + 3)
Divide by 'x'; x2+xy/x = x(x+y)
If x - 3y = 12, we can solve for x in terms of y: x = 12 + 3y. Then, to find xy, we multiply x by y: xy = y(12+3y) = 12y + 3y^2.
xy+3y+27 x and y are variables, so the only term that doesn't change with x or y is 27 y must be the same. so x being 6 and y being 3, 18+9 is 27.
X + 3y - 2y + 3y = X + (3-2+3)y = X + 4y
y = x/(x - 3) so y(x - 3) = x xy - 3y = x xy - x = 3y x(y - 1) = 3y x = 3y/(y - 1) for y ≠1 So, the inverse function is f(y) = 3y/(y - 1) where y ≠1
The solution of 4x plus 3y -9 and x -3 is; 5x+3y-3.
There is not an answer but you can factor it.3x+3y=3(x+y)
6xy(2x2 - 3y)
5
x+7x+3y-y =8x+2y =2(4x+y)
(3x + 3y)(x + y) = 3(x + y)2
-x + 3y = 6 3y = x 6 y = x/3 + 2 So slope = 1/3 and intercept = 2