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How can you find the value of y if the value of x is 1in the equation 6x-2y equals 12?
Put x = 1 in the equation. So 6*1 - 2y = 12 that is, 6 - 2y = 12 Subtract 6 from both sides: -2y = 6 Divide both sides by -2: y = 6/-2 = -6/2 = -3
How do you solve x plus y equals 10 and x subtract y equals 2 by elimination?
12
What are the steps to get y2 plus 4y-12 equals 0?
y2 + 4y -12 = 0 y2 + 6y - 2y -12 = 0 y(y + 6) -2(y +6) = 0 (y -2) x (y + 6) = 0 Hence (y-2) is zero which gives y = 2 or (y + 6) is zero which gives y = -6 The roots or solutions to the equation y2 + 4y -12 = 0 are y = 2 and y = -6
What is the value of Y in 6 plus Y equals 10-Y?
Y = 2
How do you find the solution of this system of equation -6x plus y equals -12 7x plus 8y equals 14?
Rearrange the first equation until you have y written as some function of x, then plug the answer you have for y into the second equation. Now you can solve that equation for x. Then take your new value for x and sub it into either equation. You will get your value of y. Here are the steps: -6x + y= -12 (1) 7x+8y=14 (2) Rearrange (1): y = -6 (2+x) Plug into (2) 7x+8(-6(2+x))=14 -> 7x-48(2+x) = 14 -> 7x-96+48x=14 -> 55x = 110 Thus, x = 2. Take this value of x and plug it into either equation. It will generate a value for y. Plug x = 2 into (1): -6(2)+y=-12 Therefore, y = 0. Done.
If x 2 and y -6 what is the value of 5x plus 2y?
10 + -12 = -2
What is the y-intercept of 2y-4x equals -12?
2y - 4x = -12 Algebraically rearrange to 2y = 4x - 12 Divide both sides by '2' y = 2x - 6 So at the 'y' intercept, x = 0 Substituting x = 0 We have y = 2(0) - 6 Anything multiplied '0' is equal; to '0' Hence y = 0 - 6 y = -6 is the value of the y-intercept.
How can you find the value of y if the value of x is 1in the equation 6x-2y equals 12?
Put x = 1 in the equation. So 6*1 - 2y = 12 that is, 6 - 2y = 12 Subtract 6 from both sides: -2y = 6 Divide both sides by -2: y = 6/-2 = -6/2 = -3
6y+11=23?
6y + 11 = 23 6y = 23 - 11 6y = 12 y = 12/6 y = 2.
How do you solve x plus y equals 10 and x subtract y equals 2 by elimination?
12
What are the steps to get y2 plus 4y-12 equals 0?
y2 + 4y -12 = 0 y2 + 6y - 2y -12 = 0 y(y + 6) -2(y +6) = 0 (y -2) x (y + 6) = 0 Hence (y-2) is zero which gives y = 2 or (y + 6) is zero which gives y = -6 The roots or solutions to the equation y2 + 4y -12 = 0 are y = 2 and y = -6
What is the value of Y in 6 plus Y equals 10-Y?
Y = 2
Which equation is equivalent to y plus 12 equals -3 open parenthesis x-2 close parenthesis?
y + 12 = -3(x - 2) y + 12 = -3x + 6 y = -3x - 6 or y = -3(x + 2)
What is the value if 6 plus y?
They are 2 terms of an algebraic expession in the form of: 6+y
How do you find the solution of this system of equation -6x plus y equals -12 7x plus 8y equals 14?
Rearrange the first equation until you have y written as some function of x, then plug the answer you have for y into the second equation. Now you can solve that equation for x. Then take your new value for x and sub it into either equation. You will get your value of y. Here are the steps: -6x + y= -12 (1) 7x+8y=14 (2) Rearrange (1): y = -6 (2+x) Plug into (2) 7x+8(-6(2+x))=14 -> 7x-48(2+x) = 14 -> 7x-96+48x=14 -> 55x = 110 Thus, x = 2. Take this value of x and plug it into either equation. It will generate a value for y. Plug x = 2 into (1): -6(2)+y=-12 Therefore, y = 0. Done.
What are 2 integers whose product is -72 and whose sum is 6?
ANSWER: 12 and -6x * y = 72x = 72/y Equation 1x + y = 6 Equation 2Substitute Eq.1 to Eq.2-72/y + y = 6multiply both sides of the equation by yy (-72/y + y ) = 6* y-72 + y2 = 6yy2 - 6y - 72 = 0(y- 12) (y + 6) = 0y = 12 ; y = -6x =-12 ; x = 12Take x = 12 and y = -6
2x equals 3-y 2y equals 12-x?
2x=3-y 2y=12-x y=3-2x 2(3-2x)=12-x 6-4x=12-x -3x=6 x=-2 2(-2)=3-y -4=3-y y=7 x=-2 y=7
