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For the equation ax2-2x-3, the quadratic coefficients are:
a=a,
b=-2
c=-3.

The equation of the line of symmetry is:
x= -b/2a

As we know that the line of symmetry is x=1,
we get:
1 = 2/2a, so
2a = 2
and a = 1.
We get a bowl-shaped parabola, whose lowest point is (1,-4).

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