For the equation ax2-2x-3, the quadratic coefficients are:
a=a,
b=-2
c=-3.
The equation of the line of symmetry is:
x= -b/2a
As we know that the line of symmetry is x=1,
we get:
1 = 2/2a, so
2a = 2
and a = 1.
We get a bowl-shaped parabola, whose lowest point is (1,-4).
For a quadratic equation y=Ax2+Bx+C, the line of symmetry is given by x=-B/2ASo for the equation y=-x2+x+3, B is 1 and A is -1, so the line of symmetry isx=1/2
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
It cannot.
Two: one is 0, the other is -b/a ax2 + bx + c = 0, but c = 0 ⇒ ax2 + bx + 0 = 0 ⇒ ax2 + bx = 0 ⇒ x(ax + b) = 0 ⇒ x = 0 or (ax + b) = 0 ⇒ x = -b/a
Why are Quadratic equations, which are expressed in the form of ax2 + bx + c = 0, where a does not equal 0,
The equation ax2 + bx + c = 0, where a != 0 is called quadratic.
It is a quadratic function which represents a parabola.
A discriminant that is less than zero.
The axis of symmetry for a parabola of the form y = ax2 + bx + c is x = -b/2a So the axis is x = -2/2*(-3) or x=1/3
A quadratic equation.
It is the general form of a quadratic equation.
If a = b then it is a circle; otherwise it is an ellipse.