73
7-3 = 4
73 is prime and 37 is prime.
No, reversing the order of the digits of a two-digit prime number does not always result in a prime number.
If the last three digits of a number are divisible by 8, the whole number is divisible by 8.
No. For example, reversing 23 gets 32.
Answer: 7000007Reasoning:The only odd numbers in those digits are the two 7's. The zero's are even. Therefore if you need the largest odd number possible, one of the 7's has to be the last number and one has to be the first. In which case your answer is 7000007
Integers of 6 digits are normally greater than integers of 5 digits
36
The number is 36.
The sum of any two-digit number and the number formed by reversing the digits is always divisible by 11.Why?The algebraic proof is as follows:(10x+y) + (10y+x) = 11x + 11y = 11(x+y)
73
36
No, reversing the order of the digits of a two-digit prime number does not always result in a prime number.
The answer is 39. 3+9=12, 3x9=27. 12+27=39.
It is easiest to explain with an example. Suppose you have a number 4627. Then the number obtained by reversing [the order of] its digits is 7264. The difference between them is the bigger number minus the smaller number. So here it would be 7264 - 4627 = 2637.
It is: 99
12
3 and 6
No because as for example 23 is a prime number but 32 is a composite number