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If the last three digits of a number are divisible by 8, the whole number is divisible by 8.

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Q: A number is divisible by 8 the number formed by its last?

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If the last digit of a number is 0, 2, 4, 6, 8 or 0 then the number is divisible by 2. The digit of 619 is 9, so 619 is not divisible by 2.

No. 189 is only evenly divisible by 3 and 9 (from the set provided). Using the following rules of divisibility on the number 189: Divisible by 2? No - the number is not even Divisible by 3? Yes - the sum of the digits (1 + 8 + 9 = 18) is divisible by 3 Divisible by 4? No - the last two digits are not evenly divisible by 4 Divisible by 5? No - the last digit is not a 0 or a 5 Divisible by 6? No - the number is not even Divisible by 9? Yes - the sum of the digits is divisible by 9 Divisible by 10? No - the number is not divisible by 2 or 5

18324 is divisible by both 4 and 9. 18324 / 4 = 4581 18324 / 9 = 2036 You can simply check if a number is divisible by 4 if the last two digits are divisible by 4. The last two digits are 24. 24 is divisible by 4. (24/4=6) An easy way to check if a number is divisible by 9 is if sum of the digits are divisible by 9. 18324 1+8+3+2+4 =18 18 1+8 =9 9 is divisible by 9, so 18324 is divisible by 9.

Well, to find out if any number is divisible by 3, you add up the number's factors. If the number you come up with is divisible by 3, then the entire number is divisible by 3.For example:138= 1+3+8= 1212 is divisible by 3.

The smallest whole number divisible by both 8 and 12 is 24.

Related questions

If the number formed by the last three digits is divisible by 8. Alternatively, if the number is divisible by 2, the quotient is divisible by 2 and that quotient is divisible by 2.

Numbers are divisible by 8 if the number formed by the last three individual digits is evenly divisible by 8. For example, the last three digits of the number 3624 is 624, which is evenly divisible by 8 so 3624 is evenly divisible by 8.

The number formed by the last three digits have to be divisible by 8.

If the number formed by the last three digits is divisible by 8. This requires that: if the digit in the hundreds place is even, the last two digits must form a number divisible by 8 and if the digit in the hundreds place is odd, the last two digits must form a number divisible by 4 but not by 8.

If you have a few different numbers that you are using, divide them each by 8 and if you get a whole number, that number is divisible. If you are trying to figure out what is divisible by 8, you can use a divisibility test.A number is divisible by 8 if:the number formed by the last three digits is divisible by 8.So, an example of this would be:7, 120.This number is divisible by 8 because 120 (the last 3 digits) is divisible by 8!

If the last 3 digits are divisible by 8, the number is divisible by 8.

if the last 3 digits are divisible by 8,so is the number. Ex.: 9 is not because 009 is not. 6008 is because 008 is.

Sol: 24 = 3 x 8, where 3 and 8 are co-primes. The sum of the digits in the given number is 36, which is divisible by 3. So, the given number is divisible by 3. The number formed by the last 3 digits of the given number is 744, which is divisible by 8. So, the given number is divisible by 8. Thus, the given number is divisible by both 3 and 8, where 3 and 8 are co-primes. So, it is divisible by 3 x 8, i.e., 24.

The digital root of 432 is 9 so the number is divisible by 3. The number formed by the last two digits, 32, is divisible by 4 (4*8) so 432 is divisible by 4.

A number is divisible by 8 if its last three digits form a number that is divisible by 8.

The foolproof way is to divide 4 into it. If the answer is a whole number, it's divisible by 4. You can also tell by looking at it. If the last two digits are a multiple of 4, like 24 or 80, the whole number is divisible by 4.

There is not an easy way without some division. The simplest is to check the divisibility of the number formed by the last three digits.