No, reversing the order of the digits of a two-digit prime number does not always result in a Prime number.
No. For example, reversing 23 gets 32.
As a result of the rule that you use the definition of the term - such as significant digits - when finding them for a number.
Your question is incomplete. Adding an even number with an odd number will always result in an odd number. Multiplying an even number with an odd number will always result in an even number.
A rational number is always the result of dividing an integer when the divisor is nonzero.
Yes it is... If you add the digits of ANY number together - and the result can be divided exactly by 3 or 9 - then the original number will also divide by 3 or 9. Since the digits of this number add together to make 18 - then 32643 will also divide by 3 or 9.
No because as for example 23 is a prime number but 32 is a composite number
The sum of any two-digit number and the number formed by reversing the digits is always divisible by 11.Why?The algebraic proof is as follows:(10x+y) + (10y+x) = 11x + 11y = 11(x+y)
No. For example, reversing 23 gets 32.
any of the following numbers works ...12, 23, 34, 45, 56, 67, 78, 89,
the result is always even
No, and you do not even if you reverse them.
19
When multiplying numbers with significant digits, count the total number of significant digits in each number being multiplied. The result should have the same number of significant digits as the number with the fewest significant digits. Round the final answer to that number of significant digits.
As a result of the rule that you use the definition of the term - such as significant digits - when finding them for a number.
38
It always is a negative number. The result will be the sum of the two digits with a minus sign in front of it, eg, (-4) - (+7) = -4 - 7 = -11.
This follows from the property that the set of integers is closed under addition. This means that any two integers, when added together, must always result in a whole number.