Assuming the shape is a regular rectangle, then the width of each side will be equal to (22 - (10 x 2))/2 = 1 inch.
6 inches
3.52 in. would mean 12.2 inches 3.5 in.2 would mean a square where each side is 3.5 inches long. Any shape with the same area as the square would have 3.5 in.2.
An isosceles triangle has 2 sides that are the same length and the other side does not match those other 2 side. For example, the measurements could be- 2 inches, 2 inches, and 5 inches.
8 inches
-2
Approximately 38.73 inches each side. (2 decimal places)
As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape). If you are referring to a square with an area of 11 square inches then: Using Pythagoras: diagonal² = side² + side² = 2 × side² → side² = diagonal² ÷ 2 area = side² = diagonal² ÷ 2 → diagonal² = 2 × area → diagonal = √(2 × area) = √(2 × 11 sq in) = √22 in ≈ 4.69 in If you mean an 11 inch square, ie a square with 11 inches along each side: Use Pythagoras: Diagonal² = √(2 × sidelength²) → diagonal = side_length × √2 → diagonal = 11 in × √2 ≈ 15.6 in
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All three sides have the same length. Example: each side could be 2 inches each. FALSE: one side be one inch, another be 5 inches, while the other side be 3 inches.
An octagon is a polygon with 8 sides. To find the diameter of a regular octagon when each side is 18 inches in length, you can use the formula: Diameter = Side length × √(2 + √2) Plugging in the given side length (18 inches): Diameter = 18 × √(2 + √2) ≈ 56.97 inches So, the diameter of the octagon is approximately 56.97 inches.
a+b+c 2+2+2 or 6 inches total