As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape).
If you are referring to a square with an area of 11 square inches then:
Using Pythagoras:
diagonal² = side² + side² = 2 × side²
→ side² = diagonal² ÷ 2
area = side²
= diagonal² ÷ 2
→ diagonal² = 2 × area
→ diagonal = √(2 × area)
= √(2 × 11 sq in)
= √22 in
≈ 4.69 in
If you mean an 11 inch square, ie a square with 11 inches along each side:
Use Pythagoras:
Diagonal² = √(2 × sidelength²)
→ diagonal = side_length × √2
→ diagonal = 11 in × √2 ≈ 15.6 in
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About 21.2 inches.
15 times the square root of two, all over two A formula is this: The diagonal for a square is always the sides of the square times the square root of 2
As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.
The square's diagonal is 11.314 cm
sqrt (2 x 36 x 36) ie 50.94 inches