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As no shape has been given for the area it is impossible to given the length of the diagonal - the diagonal can be ANY length greater than 0 (assuming you can define what diagonal means for the shape).

If you are referring to a square with an area of 11 square inches then:

Using Pythagoras:

diagonal² = side² + side² = 2 × side²

→ side² = diagonal² ÷ 2

area = side²

= diagonal² ÷ 2

→ diagonal² = 2 × area

→ diagonal = √(2 × area)

= √(2 × 11 sq in)

= √22 in

≈ 4.69 in

If you mean an 11 inch square, ie a square with 11 inches along each side:

Use Pythagoras:

Diagonal² = √(2 × sidelength²)

→ diagonal = side_length × √2

→ diagonal = 11 in × √2 ≈ 15.6 in

Q: What is the diagonal of 11 square inches?

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Continue Learning about Algebra

About 21.2 inches.

15 times the square root of two, all over two A formula is this: The diagonal for a square is always the sides of the square times the square root of 2

As a square has right angles, the diagonal forms a right triangle with two of the sides of the square. Therefore use Pythagoras: diagonal² = side² + side² → diagonal² = 2side² → diagonal = side × √2 Therefore to find the length of the diagonal of a square, multiply the side length of a square by the square root of 2.

The side lengths of a square with a diagonal of 16 is: 11.31.

The square's diagonal is 11.314 cm

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6.2