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If x equals y equals 2z and xyz equals 256 then what is the value of x?
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What is th ordered triple of these equations x - 2y plus 3z equals -3 2x - 3y - z equals 7 3x plus y - 2z equals 6?
The ordered triple is (x, y, z) = (1, -1, -2)
Solve the following system of equations x plus 2y -6 equals z 3y-2z equals 7 4 plus 3x equals 2y -5z?
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
3x plus 7 equals 37 x equals?
3x+7=37 -7 -7 3x=30 /3 /3 x=10
The sum of a number divided by 3 and 7 equals 5 .?
x/3 + 7 = 5 x/3 = -2 x = -6
What Given that x equals 6 is solution to 5jx plus z equals 3 evalutate the expression 60j plus 2z?
60j + 2z = 6
If x equals y equals 2z and xyz equals 256 then what is the value of x?
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What is th ordered triple of these equations x - 2y plus 3z equals -3 2x - 3y - z equals 7 3x plus y - 2z equals 6?
The ordered triple is (x, y, z) = (1, -1, -2)
Ifx equals y equals 2z then what is the value of x?
y and ½z
Solve the following system of equations x plus 2y -6 equals z 3y-2z equals 7 4 plus 3x equals 2y -5z?
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
X plus y-z equals 2 -x-5y plus 2z equals 21 5x plus 4y-4z equals 12?
I used the matrix method to find the answer: x=4, y=-7, z=-5.
Solve the system using any algebraic method a. -5x-y equals -3 ---- x-4y equals 9 b. x plus y-z equals 7 ---- 2x-3y plus z equals 2 ---- 4x plus 2y-2z equals 20?
y=5x+2 if y equals -4
What are the intercepts of the equation 4x plus 6y plus 2z equals 12?
x=3 y=2 z=6
What did David Hilbert make?
y= (7z- 1)/3 = 2z+ (z- 1)/3.x= (17y+ 1)/7 = 2y+ (3y+ 1)/7
What is the general form of the perpendicular bisector equation of the line segment of z 2z and 3z 8z?
Mid-point: (3z+z)/2, (2z+8z)/2 = (2z, 5z) Slope: (8z-2z)/(3z-z) = 6z/2z = 3 Perpendicular slope: -1/3 Equation: y -5z = -1/3(x -2z) => y = -1/3x+2z/3+5z => y = -1/3x+17z/3 General form of the bisector equation: x+3y-17z = 0
X plus 7 equals -3?
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How do you solve x plus y plus z equals 7 2x plus 3y-z equals -2 5x-6x plus 3z equals 36?
Let me see:1) x + y + z = 7 y = 7 - x- z2) 2x + 3y- z = -23) -x + 3z = 36 x = 3z - 36Subst. 3) into 2):2(3z-36)+3y -z = -2Subst 1) into 3):2(3z-36) +3(7-x-z) - z = -2Subst 3) into 2) again:6z-64 + 3(7-(3z-36) - z) -z = -2z= 67/7Subst answer into 3) -x + 3(67/7) = 36x = -51/7Subst answers into 1):-51/7 + y + 67/7 = 7y = 33/7therefore x = -51/7, y = 33/7, z = 67/7
