y and ½z
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60j + 2z = 6
Rearrange the equations in the form of: x+3y = 17z 3*(3x-y = z) Multply the second equation by 3: x+3y = 17z 9x-3y = 3z Add them together to eliminate y: 10x = 20z Divide both sides by 10: x = 2z Substitute the value of x into the original equations to find the value of y: Therefore the point of intersection is: (2z, 5z)
I used the matrix method to find the answer: x=4, y=-7, z=-5.
x=3 y=2 z=6
y=5x+2 if y equals -4