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What Given that x equals 6 is solution to 5jx plus z equals 3 evalutate the expression 60j plus 2z?
60j + 2z = 6
What is the point of intersection of 3x -y -z equals 0 and x plus 3y -17z equals 0?
Rearrange the equations in the form of: x+3y = 17z 3*(3x-y = z) Multply the second equation by 3: x+3y = 17z 9x-3y = 3z Add them together to eliminate y: 10x = 20z Divide both sides by 10: x = 2z Substitute the value of x into the original equations to find the value of y: Therefore the point of intersection is: (2z, 5z)
X plus y-z equals 2 -x-5y plus 2z equals 21 5x plus 4y-4z equals 12?
I used the matrix method to find the answer: x=4, y=-7, z=-5.
What are the intercepts of the equation 4x plus 6y plus 2z equals 12?
x=3 y=2 z=6
Solve the system using any algebraic method a. -5x-y equals -3 ---- x-4y equals 9 b. x plus y-z equals 7 ---- 2x-3y plus z equals 2 ---- 4x plus 2y-2z equals 20?
y=5x+2 if y equals -4
If x equals y equals 2z and xyz equals 256 then what is the value of x?
8
-3 X -2Z - 7 equals?
(-3) x (-2z - 7) = 6z + 21 = 3 (2z + 7)
What Given that x equals 6 is solution to 5jx plus z equals 3 evalutate the expression 60j plus 2z?
60j + 2z = 6
What is the point of intersection of 3x -y -z equals 0 and x plus 3y -17z equals 0?
Rearrange the equations in the form of: x+3y = 17z 3*(3x-y = z) Multply the second equation by 3: x+3y = 17z 9x-3y = 3z Add them together to eliminate y: 10x = 20z Divide both sides by 10: x = 2z Substitute the value of x into the original equations to find the value of y: Therefore the point of intersection is: (2z, 5z)
X plus y-z equals 2 -x-5y plus 2z equals 21 5x plus 4y-4z equals 12?
I used the matrix method to find the answer: x=4, y=-7, z=-5.
Solve this system of equations 5x plus 3y plus z equals -29 x-3y plus 2z equals 23 14x-2y plus 3z equals -18?
Solve this system of equations. 5x+3y+z=-29 x-3y+2z=23 14x-2y+3z=-18 Write the solution as an ordered triple.
Solve the following system of equations x plus 2y -6 equals z 3y-2z equals 7 4 plus 3x equals 2y -5z?
x+2y-6=z -z -z x+2y-z-6=0 +6 +6 ---------> x+2y-z=6 3y-2z=7 ---------> 0x+3y-2z=7 4+3x=2y-5z -3x -3x ---------> -3x+2y-5z=4 Put them into a matrix, for x,y,z and their answers. Solve for [A]-1[B], and the answer comes to: x= 1.75, y= 1.5, and z= -1.25
What are the intercepts of the equation 4x plus 6y plus 2z equals 12?
x=3 y=2 z=6
What is th ordered triple of these equations x - 2y plus 3z equals -3 2x - 3y - z equals 7 3x plus y - 2z equals 6?
The ordered triple is (x, y, z) = (1, -1, -2)
Which classifaction best describes the following system of equations x-y-z equals 0 2x-y plus 2z equals 1 x-y plus z equals -2 is it consistent incosistnet dependent or independent?
1st equation: x-y-z = 0 2nd equation: 2x-y+2z = 1 3rd equation: x-y+z = -2 They appear to be simultaneous equations dependent on each other for the solutions which are: x = 4, y = 5 and z = -1
If x equals 3 What is the value of x?
the value of x is 3
What does X plus X equals?
It equals 2x. For an exact numerical value, multiply the value of x by 2 to get the result.
