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1. c 2. d 3. d 4. b 5. STUDY STUDY STUDY FOR THE REST OF THE ANSWERS
4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6 4!/(2!*2!) = 4*3*2*1/(2*1*2*1) = 6
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14xy - 21x + 7 '7' is a common factor to all three coefficients. So 'take it out'. Hence 7(2xy - 3x + 1) The rest of it , inside the brackets does not factor. However, I suspect the 'y' should be a 'power of 2' Hence 7(2x^(2) - 3x + 1) This factors to 7(2x - 1)(x - 1) Fully factored.!!!!
1. yes 2.yes 3. no 4.a 5.c 6.a 7-12 can't graph 13.y<1 y<=-4 not sure if #13 is correct but the rest is. Hope this helped. :)