0
14xy - 21x + 7
'7' is a common factor to all three coefficients. So 'take it out'.
Hence
7(2xy - 3x + 1)
The rest of it , inside the brackets does not factor.
However, I suspect the 'y' should be a 'power of 2'
Hence
7(2x^(2) - 3x + 1)
This factors to
7(2x - 1)(x - 1) Fully factored.!!!!
(7x+2)(2y-1)
Add your answer:
Earn +20 pts
Factorise x squared plus 13x plus 42?
It is (x+6)(x+7) when factored
How do you factorise 2xy - 6x plus 7y -21?
2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
Factorise 5x squared plus 17x plus 6?
(5x + 2)(x + 3)
How do you factorise x2 plus 4x?
X2 + 4xx(x + 4)=======
Factorise x squared plus 6x plus 5?
It is (x+5)(x+1) when factored
How do you Factorise p2 plus 10d plus 7?
p2+10d+7
Factorise x2 - 10x plus 21?
(x-7)(x-3)
Factorise x squared plus 13x plus 42?
It is (x+6)(x+7) when factored
Factorise 2x plus 7 plus 5?
2x + 7 + 5 = 2x + 12 = 2*x + 2*6 = 2*(x+6)
How do you factorise 2x squared minus 13x plus 21?
(x - 3)(2x - 7)
How do you factorise 2xy - 6x plus 7y -21?
2x(y - 3) + 7(y - 3) = (2x + 7)(y - 3)
Factorise a a plus 10a plus 24?
(a + 6)(a + 4)
How do you factorise 3x plus 15?
X=5
Factorise x2 plus 8x plus 15?
(x+5)(x+3)
How do you factorise -4csq plus 8c?
4c(-sq+2)
How do you factorise xy plus 3x?
To factorize xy + 3x, we first need to factor out the common factor, which is x. This gives us x(y + 3). Therefore, the factorized form of xy + 3x is x(y + 3).
How do you factorise 3t plus 9?
It is: 3(t+3)
