4
x² - 18x - 4 = o x² - 18x = 4 x² - 18x + (18/2)² = 4 + (18/2)² x² - 18x + 81 = 4 + 81 (x - 9)² = 85 x - 9 = ±√85 x = 9 ±√85 x = 9 + √85 or x = 9 - √85 if you are still confused, i want you to follow the related link that explains the concept of completing the square clearly.
An equation to figure out what the answer of "x" is. eg, Removing the brackets - 6(3x-2) = 2(8x+4) 18x-12 = 16x + 8 18x-16x = 8+12 2x = 20 x = 10
Yes and it is 4(5x-7) when factored
First we need to find the equation of the tangent line to the parabola at (2, 20).Step 1. Take the derivative of the function of the parabola.Let f(x) = 5x^2f'(x) = 10xStep 2. Find the slope of the tangent line at x = 2. Evaluate f'(2).f'(2) = 2 x 10 = 20Step 3. Using the slope, m = 20, and the point (2, 20), find the equation of the tangent line at that point. Use the point-slope form of a line(y - y1) = m(x - x1)(y - 20) = 20(x - 2)y - 20 = 20x - 40 add 20 to both sidesy = 20x - 20Step 4. Find the points of intersections of y = 5x^2 and y = 20x - 205x^2 = 20x - 20 Divide by 5 to both sidesx^2 = 4x - 4 subtract 4x and add 4 to both sidesx^2 - 4x + 4 = 0 factor(x - 2)^2= 0x = 2Step 5. Find the intersection of the tangent line with x-axis.y = 20x - 20y = 020x - 20 = 0x = 1Since the vertex of the parabola is (0, 0) and the intersection of the tangent line with parabola is (2,20) we use the interval [0, 2] to fin the required area.Step 6. IntegrateA = ∫ [(5x^2)] dx, where the below boundary is 0, and the upper boundary is 2 minus A= ∫ (20x + 20)] dx from 1 to 2= 10/3
The question is utter nonsense! The perimeter of is a 1-dimensional measure so it cannot be 20x 2 28x 8. Similarly, the length of the running space is also a linear measure and so it cannot be 10x 4. There is, therefore, no way that the answer can be correct.
Divide all terms by 2 and it can then be factored to (2x+1)(5x+2)
x² - 18x - 4 = o x² - 18x = 4 x² - 18x + (18/2)² = 4 + (18/2)² x² - 18x + 81 = 4 + 81 (x - 9)² = 85 x - 9 = ±√85 x = 9 ±√85 x = 9 + √85 or x = 9 - √85 if you are still confused, i want you to follow the related link that explains the concept of completing the square clearly.
x2 + 20x + 4 = 0 x2 + 20x + 100 = 96 (x + 10)2 = 96 x + 10 = ±961/2 x = -10 ±961/2 x = -10 ±4√6
Factorises as (5x-2)(5x-2) so x = 0.4 25x2= 4, -20x = -8 4 - 8 + 4 = 0
12x2-20x-8 = (12x+4)(x-2)
4xx-18x+8 2(2xx-9x+4) 2(2xx-8x-1x+4) 2(2x(x-4)-1(x-4)) 2(2x-1)(x-4)
5x^2 + 20x
-x=-2
x=4 and x =7Improved Answer:-x2-18x-40 = (x+2)(x-20) when factored
The factor is 2x^2(x^2-9)
3x**4+18x 3x(x**3+6)
(x+9)^2 =x^2 + 9 X^2 + 18x + 81 = X^2 +9 18X + 72 = 0 18X = -72 X =- 4