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12x2-20x-8 = (12x+4)(x-2)

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Q: What is the quadratic trinomials factor of 12xsquared-20x -8?
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How do you factor 21x2 -59x 8?

If you mean: 21x2-59x+8 then it is (3x-8)(7x-1) when factored Making use of the quadratic equation formula will help


How do i factor the expression y2 plus 6y-16?

It is: (y+8)(y-2) and knowing how to use the quadratic equation formula does help.


What're examples of quadratic equation?

x*2+4x+8= 0 is a quadratic equation


How do you factor x squared plus 16x minus 348?

x2 + 16x - 348 cannot be factored. Solving for x with the quadratic formula results in x = -8 - 2√103 and x = -8 + 2√103


How will you factor quadratic trynomial?

If the leading coefficient is 1 (or you don't see any number in front of x^2) then find 2 factors f1,f2 which multiply to get the constant term, c, and add to get the coefficient of x, or b,. Then the factors would be (x+f1)(x+f2). Always watch for negatives. Example: x^2 + 2x - 8 B= 2 C= -8 We want 2 numbers that multiply to -8 and add to 2. Since they multiply to a negative number, one must be positive and one must be negative. Since the sum is positive, the larger must also be positive. Analyzing signs can help with determining the factors. With our example, the factors would be 4, -2 so the factor of x^2 + 2x - 8 is (x + 4)(x - 2) To factor quadratic trinomials with a coefficient of the quadratic term , other than 1, I would try the AC method. Here is an example Factor 2x^2 - 3x - 2 With the AC method, find the product of the a, the coefficient of the quadratic term, and c, the constant Here AC = 2*-2 = -4 Then find your b, or coefficient of x B = -3 AC = -4 B = -3 To factor, you need to find a pair of factors that multiply to get AC but adds up to B Our factors would be -4 and 1 since -4*1 = -4 and -4 + 1 = -3 Then rewrite your factors (Ax + f1)(Ax + f2) where f1, f2 are the factors you just found. For our example, (2x - 4)(2x + 1). Finally, factor out any common factor from each binomial (here we can factor 2 out of 2x-4 to get (x - 2)(2x +1)) If this doesn't work, resort to the Quadratic Formula. The factors are then (x - (-b + sqrt(b^2-4ac))/2a)(x - (-b - sqrt(b^2 - 4ac))/2a)

Related questions

Factoring trinomials x2 4x - 32?

(x+8)(x-4)


How do you factor 21x2 -59x 8?

If you mean: 21x2-59x+8 then it is (3x-8)(7x-1) when factored Making use of the quadratic equation formula will help


15Y2 plus 26y plus 8 greatest common factor?

using the quadratic formula -4/3 and -0.4


How do i factor the expression y2 plus 6y-16?

It is: (y+8)(y-2) and knowing how to use the quadratic equation formula does help.


What method(s) would you choose to solve the quadratic equation -2x2 8x 130?

I'd substitute the values -2, 8 and 130 into the quadratic formula and wind up with two real solutions: 2 plus or minus -1 times the square root of 69 x = -6.306623862918075 x = 10.306623862918075


How do you factor 3xsqrd plus 8x-8?

3x2 + 8x - 8 doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (-4 plus or minus 2 times the square root of 10) divided by three.x = 0.7748517734455863x = -3.441518440112253


What're examples of quadratic equation?

x*2+4x+8= 0 is a quadratic equation


How do you factor x squared plus 16x minus 348?

x2 + 16x - 348 cannot be factored. Solving for x with the quadratic formula results in x = -8 - 2√103 and x = -8 + 2√103


How will you factor quadratic trynomial?

If the leading coefficient is 1 (or you don't see any number in front of x^2) then find 2 factors f1,f2 which multiply to get the constant term, c, and add to get the coefficient of x, or b,. Then the factors would be (x+f1)(x+f2). Always watch for negatives. Example: x^2 + 2x - 8 B= 2 C= -8 We want 2 numbers that multiply to -8 and add to 2. Since they multiply to a negative number, one must be positive and one must be negative. Since the sum is positive, the larger must also be positive. Analyzing signs can help with determining the factors. With our example, the factors would be 4, -2 so the factor of x^2 + 2x - 8 is (x + 4)(x - 2) To factor quadratic trinomials with a coefficient of the quadratic term , other than 1, I would try the AC method. Here is an example Factor 2x^2 - 3x - 2 With the AC method, find the product of the a, the coefficient of the quadratic term, and c, the constant Here AC = 2*-2 = -4 Then find your b, or coefficient of x B = -3 AC = -4 B = -3 To factor, you need to find a pair of factors that multiply to get AC but adds up to B Our factors would be -4 and 1 since -4*1 = -4 and -4 + 1 = -3 Then rewrite your factors (Ax + f1)(Ax + f2) where f1, f2 are the factors you just found. For our example, (2x - 4)(2x + 1). Finally, factor out any common factor from each binomial (here we can factor 2 out of 2x-4 to get (x - 2)(2x +1)) If this doesn't work, resort to the Quadratic Formula. The factors are then (x - (-b + sqrt(b^2-4ac))/2a)(x - (-b - sqrt(b^2 - 4ac))/2a)


Is 3x plus 2y equals 8 a quadratic function?

3x + 2y = 8 2y=8-3x y=4-1.5x A quadratic has x^2 This is the equation of a line with negative slope.


Is 3x plus 27 equals 8 a quadratic function?

No it is a linear one. X^2 = quadratic, x = linear. So if the equation doesn't have an x squared, then it is not quadratic.


How do you factor x squared plus 16x minus 416?

That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: -8 plus or minus 4 times the square root of 30. x = 13.908902300206645 x = -29.908902300206645