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What are the factors of 25x2 plus 40x plus 16?
The factorization of 25x2 + 40x + 16 is (5x+4)(5x+4).
6x plus 12x plus 2x equals 80?
6x + 12x + 2x = 80 20x = 80 x = 4
What does negative 4 plus 4 equal?
-4 plus 4 equals zero.
What is 4x equals 20?
4x = 20 x = 5 (divide both sides by 4)
5x plus y equals 26 x plus 5y equals -14?
(6, -4)
25x2-20x plus 4 equals 0?
Factorises as (5x-2)(5x-2) so x = 0.4 25x2= 4, -20x = -8 4 - 8 + 4 = 0
Factor 25x2 plus 40x plus 16?
25x2 + 40x + 16 = 25x2 + 20x + 20x + 16 = 5x(5x + 4) + 4(5x + 4) = (5x + 4)(5x + 4) or (5x + 4)2
25X2 plus 20X plus 4 equals 0?
This quadratic equation can be solved by three methods: (a) factoring (b) completing the square (c) using the quadratic equation formula.Factoring:25x2+20x+4 = 0(5+2)(5x+2) = 0Solution: x = -2/5 also x = -2/5 (they both have equal roots)
What is the value of m in 25x2-20x plus m equals 0 so that the two roots are equal?
4 and the two equal roots are 2/5 and 2/5
What is the answer to 20x plus 5-20 equals 21x plus 4?
20x + 5 - 20 = 21x + 4 -x = 4 + 15 x = -19
Value of the discriminant 50x² equals 20x-2 equals?
Standard form is y=ax2+bx+c50x2=20x-250x2-20x+2=02(25x2-10+1)=0Discriminant is b2-4ac(-10)2-4(25)(1) = 0Discriminant is 0 and the function has two real zeros.
What are the factors of 25x2 plus 40x plus 16?
The factorization of 25x2 + 40x + 16 is (5x+4)(5x+4).
What is 20x plus 80y equals 0 in y equals mx plus b?
20x + 80y = 0Subtract 20x from each side of the equation:80y = -20xDivide each side by 80:y = -1/4 xm = -1/4b = 0
X2 plus 20x plus 4 equals 0?
x2 + 20x + 4 = 0 x2 + 20x + 100 = 96 (x + 10)2 = 96 x + 10 = ±961/2 x = -10 ±961/2 x = -10 ±4√6
How much is 6 plus 4 6 plus 4 25x2?
106
How much is 6 plus 4 then 6 plus 4 - 25x2?
If it's written like this (6+4)(6+4) - (25x2) Then the answer will be: 10x10 - 50 100 - 50 = 50
6x plus 12x plus 2x equals 80?
6x + 12x + 2x = 80 20x = 80 x = 4
