This quadratic equation can be solved by three methods: (a) factoring (b) completing the square (c) using the quadratic equation formula.
Factoring:
25x2+20x+4 = 0
(5+2)(5x+2) = 0
Solution: x = -2/5 also x = -2/5 (they both have equal roots)
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50x squared equals 20x-2 equals zero is not possible, for 20x-2 = 0 --> x = 1/10 While 50x2 = 0 means that x should be zero. So either 50x2 =/ 20x-2 or 20x-2 =/ 0
x2 + 20x - 39 = 0: Add 61 giving: x2 + 20x + 100 = (x + 10)2
5x2 + 20x = 0 5x(x + 4) = 0 x = 0 and -4
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
If: y = 10x -12 and y = x^2 +20x +12 Then: x^2 +20x +12 = 10x -12 Transposing terms: x^2 +10x +24 = 0 Factorizing: (x+6)(x+4) = 0 => x = -6 or x = -4 Points of intersection by substitution are at: (-6, -72) and (-4, -52)