2a+3b+4c cannot be added. They are not like terms. Like terms need to have the same variable in order to be added.
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It cannot be simplified any further so it is: 3a + 24b + 4c
4 cc
5P + 111 + 136 + 20 = 4c + 4 5P + 267 = 4c + 4 -4 -4 5P + 263 = 4c You cannot cimplify it anymore, unless by 'c' you meant 'P'. 5P + 263 = 4P -5P -5P 263(-1) = -P(-1) -263 = P
4C times D is the same as 4CD in algebra which means 4*D*C
The solution to this equation can not be determined
Gathering like terms together, this is equal to 5a + 3b + 7c.
(5a - 4b) + (2c - 3b - 6c) + a =5a - 4b + 2c - 3b - 6c + a =(5a + a) + (-4b - 3b) + (2c - 6c) =[ 6a - 7b - 4c ].
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b+b+b+c+c+c+c =3b+4c
b + b + b + c + c + c + c = 3b + 4c
2a + 4b + 8c = 2(a + 2b + 4c) You could also continue by factoring the inside of the parentheses a bit: 2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])
That's going to depend on the values of 'a', 'b', 'c', and 'f'.
(5a)(2z) - (4a)(2c) + 15xz - 12xc group and factor each group = 2a(5z - 4c) + 3x(5z - 4c) factor again (5z - 4c)(2a + 3x)
2a + 2b = 26 2b + c = 22 ===> b = 11 - c/2 4c + 2b = 46 ===> b = 23 - 2c From the 2nd and 3rd equations: 11 - c/2 = 23 - 2c 22 - c = 46 - 4c 22 - 46 = -4c + c ===> -24 = -3c ===> c = 8 Substitute c=8 into the 3rd equation: b = 23 - 16 = 7 Substitute b=7 into the 1st equation: 2a + 14 = 26 2a = 12 ===> a = 6
A level 5a is higher. This is how it works: n 1c 1b 1a 2c 2b 2a 3c 3b 3a 4c 4b 4a 5c 5b 5a ect. Student from BGP. N.S.S
4c+2 = 3c+9 4c-3c = 9-2 c = 7
4c+1-5+2c = 6c-4.