Best Answer

2a + 4b + 8c = 2(a + 2b + 4c)

You could also continue by factoring the inside of the parentheses a bit:

2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])

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2a+4b

2(a)+4(b)

6(a + b)+8(c)

14(a + b + c)

It is because ''a ,b ,c'' cannot be added, divided and subtracted

Q: How do you factorise 2a plus 4b plus 8c?

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8c cubed

Actually, its not just dependent on the cup size...Relatively speaking, for teenage girls, a C cup is average/large, however there are a huge range of other sizes going up to H!! The appearance of a size also depends on the length aroudn your chest, measured in numbers, the smallest I know of is 8, so if you're and 8C its not very big, however if you were to be a 16C it would be very very big, so it all depends on the combination of cup size and chest size.

Related questions

4c(-sq+2)

6

It is an expression that can be simplified to: 1-4b-5c

There is no answer because the question contains what appear to be two expressions in 2 variables. There are no equations nor inequalities and so there is nothing which can be solved.

It is: 6-11+5-8c+9c = c

What is the answer

8c

-8c + 1 = -3 => -8c = -3 + 1 => -8c = -2 => c = -2/(-8) => c = 1/4 = 0.25

8c + 24 + 23 = 71subtract 47 from each side, 8c = 24divide each side by 8, c = 3

It is 7 - 8c.

It is 7 - 8c.

-8c+1 = -3 -8c = -3-1 -8c = -4 Divide both sides by -8 in order to find the value of c remembering that a minus number divided into minus number is equal to a plus number: c = 1/2