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Q: How do you factorise 2a plus 4b plus 8c?

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4c(-sq+2)

6

It is an expression that can be simplified to: 1-4b-5c

There is no answer because the question contains what appear to be two expressions in 2 variables. There are no equations nor inequalities and so there is nothing which can be solved.

It is: 6-11+5-8c+9c = c

What is the answer

8c

-8c + 1 = -3 => -8c = -3 + 1 => -8c = -2 => c = -2/(-8) => c = 1/4 = 0.25

It is 7 - 8c.

8c + 24 + 23 = 71subtract 47 from each side, 8c = 24divide each side by 8, c = 3

It is 7 - 8c.

-8c+1 = -3 -8c = -3-1 -8c = -4 Divide both sides by -8 in order to find the value of c remembering that a minus number divided into minus number is equal to a plus number: c = 1/2

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