How do you factorise 2a plus 4b plus 8c?

Answer 1

2a + 4b + 8c = 2(a + 2b + 4c)

You could also continue by factoring the inside of the parentheses a bit:

2a + 4b + 8c = 2(a + 2b + 4c) = 2(a + 2[b + 2c])

Answer 2

2a+4b

2(a)+4(b)

6(a + b)+8(c)

14(a + b + c)

It is because ''a ,b ,c'' cannot be added, divided and subtracted