40m^3
5m+2n, n-3m, 7-3n (5m+2n)+(n-3m)+(7-3n)=2m+7
The volume of a box is calculated by multiplying its length, width, and height. In this case, the box is 3m long, 5m high, and 2m wide. Therefore, the volume of the box would be 3m x 5m x 2m = 30 cubic meters.
It is simply: 5m+2
8m + 3n - 5m + 10n = 3m +13n
5m = 2m - 153m = -15m = -15/3m = -5
5m-3x+3m+2x 2m-x
5m-12n
5m2 - 17m + 12 = 0∴ 5m2 - 5m - 12m + 12 = 0∴ 5m(m - 1) - 12(m - 1) = 0∴ (5m - 12)(m - 1) = 0∴ m ∈ {1, 12/5}
5m + 7 - 2m - 1 = 3m + 6
To solve the equation 5m + 3 = 3m + 9, you need to isolate the variable m. Start by subtracting 3m from both sides to get 2m + 3 = 9. Then, subtract 3 from both sides to get 2m = 6. Finally, divide by 2 to find m = 3.
Assuming you mean 2m2... (2m - 3)(m + 4)
(10, 2)
40m^3
5m-7m = 12 -2m = 12 -2m/-2 = 12/-2 m = -6
1m = 100cm 2m = 200cm 3m = 300cm So: 200cm+300cm=500cm Or 2m + 3m=5m
2m x 5m = 10 sq. m.