The constant term of the trinomial
prime
x2+14x+49 = (x+7)(x+7) when factored
x2-18x+81 = (x-9)(x-9) when factored
If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)
The constant term of the trinomial
prime
x2+14x+49 = (x+7)(x+7) when factored
x2-18x+81 = (x-9)(x-9) when factored
If you mean x^2 -12x+35 then it is a quadratic expression which can be factored in the form of (x-7)(x-5)
Yes; the factored form would be (9c+4)(9c+4) or just (9c+4)2 Since the two factors are the same, the beginning trinomial 81c2+72c+16 is a perfect square trinomial
It is: 2x2+4x+2 by dividing all terms by 2 it is then (x+1)(x+1) when factored
It is a quadratic expression and can be factored into: (3x+1)(x+2)
(X + 2)(X + 4) Factored
No.
The given quadratic expression can not be factored as a perfect square.
5x2+11x+2 = (5x+1)(x+2) when factored