2x+3y=13
3x-y=3
x=2
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3x+5 = 2x+13 3x-2x = 13-5 x = 8
2x + 1 = 13; 2x = 12; x = 6
[ y = 2x plus or minus any number ] is parallel to it. [ y = -0.5x plus or minus any number ] is perpendicular to it.
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If: x+y = 8 and 2x-y = 5 Then by adding the equations together: 3x = 13 or x = 13/3 By substitution into the original equations: x = 13/3 and y = 11/3