2x + 1 = 13; 2x = 12; x = 6
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∙ 10y ago84
y = 2x -1 y = 5x -13 So: 5x -13 = 2x -1 5x -2x = 13 -1 3x = 12 x = 4 and by substituting y = 7
2x+1 = 9 2x = 9-1 2x = 8 x = 4
(5, 1)
(2, 1)
The answer to 1 over 2x plus 13 equals 9 is x equals -8.
2x plus 3y
4+2x-2x+1=13+6 Combine like terms. (4+1=5; 2x-2x=0; 13+6=19) 5=19 This problem has no solution.
84
(4 + 2x) - (-2x + 1) = 13 + 6 4 + 2x + 2x -1 = 19 4x +3 = 19 4x = 19 - 3 4x = 16 therefore x = 16/4 x = 4
3x+1+2x-2 = 64 3x+2x = 64-1+2 5x = 65 x = 13
x=1
x = 0
-2x plus 3y equals 1
x = 8, y = -1
x=5.54x+1= 2x+12-1 -14x=2x+11-2x -2x2x=11/2 /2x=5.5
NM equals 2x + 1, as stated in the question!