2x + x + 4 +2x = x + 20 5x + 4 = x + 20 5x - x = 20 - 4 4x = 16 x = 4
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-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
x2+2x-4 = 0 x = (-2 plus/minus sqrt (4-(4x1x-4)) / 2 x = (-2 plus/minus sqrt 20)/2 x = (-2 - sqrt 20)/2 or (-2 + sqrt 20)/2 x = -3.236 or 1.236
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2x^2 + 3x - 20 = 0 is 2x^2 + 8x - 5x -20 = 0 is 2x(x + 4) -5(x + 4) = 0 is (2x - 5)(x +4) = 0 Hence 2x -5 = 0 which gives x = 2.5 or x + 4 = 0 which gives x = -4
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines