2x^2 + 3x - 20 = 0 is
2x^2 + 8x - 5x -20 = 0 is
2x(x + 4) -5(x + 4) = 0 is
(2x - 5)(x +4) = 0
Hence 2x -5 = 0 which gives x = 2.5 or x + 4 = 0 which gives x = -4
X = √63
This is the common form of the Pythagorean Theorem. It describes the relationship between the two legs of a right triangle and the hypotenuse.
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
(2, -2)
7(3y-2)-(-4y+9)
-2, 1.74 and 0.46
Yes.
104
The vertex is at the point (0, 4).
Y = x squared -4x plus 3 is an equation of a function. It is neither called a domain nor a range.
89
pythagoras
b= 10
X = √63
b = 14324.80366
2 squared plus 2 x 3 = 10, 7 squared plus 7 x 2 = 63, 6 squared plus 6 x 5 = 66,8 squared plus 8 x 4 = 96 so 9 squared plus 9 x 7 = 81 + 63 = 144.
16