(x23)'=23x22 Generally, (xn)'=n*xn-1
Let the length be 3x and the width be x: 3x*x = 243 3x2 = 243 Divide both sides by 3: x2 = 81 Square root both sides: x = 9 Therefore: length = 27 cm and width = 9 cm
Let its width be x:- 2(2x+x) = 54 => 4x+2x = 54 => 6x = 54 => x = 9 Therefore: width = 9 cm and length = 18 cm
Let the other diagonal be x If: 0.5*12*x = 30 then x = 60/12 => x = 5 The rhombus has four interior right angle triangles with lengths of 6 cm and 2.5 cm Using Pythagoras each equal sides of the rhombus works out as 6.5 cm Perimeter: 4*6.5 = 26 cm
Perimeter of rectangle = 2 x ( L + W ) = 2 x 64 = 128 cm. or Perimeter of rectangle = 2L + 2W = 68 + 60 = 128 cm.
Area: 54 square cm Perimeter: 30 cm
Volume = 10 cm x 9 cm x 30 cm = 2700 cm3
81 cm
The variables are x and y
20 x 30 = 600 square cm
(60-cm x 60-cm x 30-cm) x (1 inch/2.54 cm)3 x (1 foot/12 inches)3 = 3.814 foot3(rounded)
2.54 cm = 1 in (exactly) 30 cm x 40 cm x 10 cm = (30 ÷ 2.54) in x (40 ÷ 2.54) in x (10 ÷ 2.54) in ≈ 11.811 in x 15.748 in x 3.937 in
1 inch = 2.54 cm Answer = (9 x 2.54) cm x (13 x 2.54) cm
3 x 100 x 100 cm = 30 000 cubic cm 1 liter = 1000 cubic cm Answer = 30 000 cubic cm = 30 000/1000 liters = 30 liters
40 cm x 40 cm x 30 cm is equivalent to approximately 15.75 inches x 15.75 inches x 11.81 inches.
To find the volume of a rectangular solid, you multiply the length, width, and height. 170 cm x 127 cm x 30 cm = 648,900 cubic centimeters.
The standard for conversion of metric (cm) to Imperial (inches) is 1 inch = 2.54 cm. Hence 30 cm x 40 cm x 10 cm = 30/2.54 X 40 / 2.54 x 10 /2.54 = 11.811 ins. X 15.748 ins. X 3.937 ins. As an approximation 12 ins. X 16 ins. X 4 ins.