3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
3x+4y = 17 -3x -3x 4y = -3x+17 Divide each TERM by 4 y = -3x + 17 4 4
2x
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
(27x3 - 64) = [(3x)3 - 43] = (3x - 4)[(3x)2 + (3x)(4) + 42] = (3x - 4)(9x2 + 12x + 16)
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
3x - y = 4 Get y by itself to see if it is the same as y = 3x - 4: 3x = 4 + y 3x - 4 = y Therefore, 3x - y = 4 is the equivalent of y = 3x - 4.
3x+4y = 17 -3x -3x 4y = -3x+17 Divide each TERM by 4 y = -3x + 17 4 4
2x
2x
3x+4y = 17 -3x -3x 4y = -3x+17 Divide each TERM by 4 y = -3x + 17 4 4
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
Solve:4 - 3x = 104 - 3x - 4 = 10 - 4-3x = 6-3x/-3 = 6/-3x = -2Check:4 - (3 x -2) = 104 - (-6) = 104 + 6 = 1010 = 10
It is: 3x+4
3x - y = -4 3x - y = 0 Those lines do not intersect. They are parallel. You can demonstrate by solving either of them for one of the two variables, then plugging it's value into the other: 3x - y = -4 ∴y = 3x + 4 Now substitute: 3x - y = 0 ∴ 3x - (3x + 4) = 0 ∴ 3x - 3x - 4 = 0 ∴ -4 = 0 This result is obviously incorrect, indicating that the lines do not intersect.
3x + 4= 7 3x= 7-4 3x/3 = 3/3 x=1