So, we have 3x = 4 for some number x. We will solve for x. 3x = 4 (1/3)*(3x) = (1/3)*(4) [multiplied by (1/3) on both sides] x = 4/3
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3x * (x - 4) = 3x*x - 3x*4 = 3x^2 - 12x.
3x+4y = 17 -3x -3x 4y = -3x+17 Divide each TERM by 4 y = -3x + 17 4 4
2x
-3x+14 = -4 -3x = -4-14 -3x = -18 x = 6
(27x3 - 64) = [(3x)3 - 43] = (3x - 4)[(3x)2 + (3x)(4) + 42] = (3x - 4)(9x2 + 12x + 16)