3x - y = -4
3x - y = 0
Those lines do not intersect. They are parallel. You can demonstrate by solving either of them for one of the two variables, then plugging it's value into the other:
3x - y = -4
∴y = 3x + 4
Now substitute:
3x - y = 0
∴ 3x - (3x + 4) = 0
∴ 3x - 3x - 4 = 0
∴ -4 = 0
This result is obviously incorrect, indicating that the lines do not intersect.
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It works out that they intersect at: (4, -7)
the north pole is the place where the 2 0 degree lines intersect
2x^2+3xy-4y2(4)+3(2)(-4)-(4)(-4)8-24+16=0
x = -1 and y = 2 The lines intersect at (-1, 2)
By graphing the lines on the coordinated plane they will intersect at (2, -4) which is the solution of the equations